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If z1,z2 and z3  are any three complex numbers then the fourth vertex of the parallelogram. Whose three vertices taken in order are z1,z2,z3  is

a
z1−z2+z3
b
z1+z2+z3
c
13   (z1−z2+z3)
d
13   (z1+z2−z3)

detailed solution

Correct option is A

Since the diagonals of a parallelogram bisect each of other, therefore,z1+z32  =  z2+z42⇒  z4=z1−z2+z3.

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