If z1,z2 and z3 are any three complex numbers then the fourth vertex of the parallelogram. Whose three vertices taken in order are z1,z2,z3 is

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z1−z2+z3

z1+z2+z3

13 (z1−z2+z3)

13 (z1+z2−z3)

answer is A.

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Detailed Solution

Since the diagonals of a parallelogram bisect each of other, therefore,z1+z32 = z2+z42⇒ z4=z1−z2+z3.

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