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Q.

If z1+z2+z3=0 and z1=z2=z3=1, then value of z12+z22+z32 equals

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a

-1

b

0

c

1

d

3

answer is B.

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Detailed Solution

z12+z22+z32=z1+z2+z32−2z2z3+z3z1+z1z2=0−2z1z2z31z1+1z2+1z3=−2z1z2z3z¯1+z¯2+z¯3=−2z1z2z3(0)=0 ∵z1=z2=z3=1
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