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The image of the centroid of the triangle whose ortho centre is at origin and the circum centre at in the line which is equally inclined with axes in the first quadrant is
detailed solution
Correct option is A
In any triangle the centroid G divides the line segment joining ortho center Oand the circum centre S in the ratio 2:1It implies G=mx2+nx1m+n,my2+ny1m+n=23+101+2,23+101+2=2,2 Equation of the line which is equally inclined, means making equal angles with axes in the first quadrant is x=yThe image of the point Px1,y1 in the line x=yis y1,x1The image of G=2,2 in the line x=y is 2,2Talk to our academic expert!
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The images of on the line is and the image of Q on the line is R. Then the midpoint of PR is
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