The image of the line  2x−y−1=0 with respect to the line 3x−2y+4=0  is

The image of line lx+my+n=0  with respect to the line ax+by+c=0  is   a2+b2lx+my+n=2al+bmax+by+c=0Hence the image of the line   with respect to the line   is 32+−222x−y−1=232+−2−13x−2y+4132x−y−1=163x−2y+426x−13y−13=48x−32y+6422x−19y+77=0 Compare 22x−19y+77=0  with  px+qy+r=0It implies that  p=22,q=−19,r=77Therefore,   p+q+r=22−19+77=80