The image of the point having position vector i¯+3j¯+4k¯ in the plane r¯.(2i¯−j¯+4k¯)+3=0

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−3i¯+5j¯+k¯

−3i¯+5j¯+2k¯

3i¯+5j¯+k¯

3i¯+5j¯+2k¯

answer is B.

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Detailed Solution

(x1,y1,z1)=(1,3,4) plane 2x−y+z+3=0If (h,k,l) in the image of (x1,y1,z1)⇒h−x1a=k−y1b=l−z1c=−2(ax1+by1+cz1+d)a2+b2+c2

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