The image of the point (−1,3,4) in the plane x−2y=0 is
−173,−193,1
95,−135,4
−173,−193,4
(15,11,4)
Given (x1,y1,z1)=(−1,3,4)
∴h+11=k−3−2=l−40=−2(−1−2(3))1+4+0
⇒h+11=k−3−2=l−40=−2(−1−2(3))1+4+0
⇒(h,k,l)=95,−135,4