Image of the point (–1, 3) with respect to the line y=2x is
(7/5, 14/5)
(1, 2)
(3, 1)
(5, 1)
Equation of the line through (–1, 3) perpendicular
to y=2x is x+2y=5 which mets y=2x at
(1, 2). Required point is (α,β) such that α−12=1,
β+32=2.