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Image of the point (–1, 3) with respect to the line $y = 2 x$ is

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(1, 2)

(3, 1)

(5, 1)

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Correct option is C

Equation of the line through (–1, 3) perpendicularto y=2x is x+2y=5 which mets y=2x at (1, 2). Required point is (α,β) such that α−12=1,β+32=2.

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Image of the point (–1, 3) with respect to the line y=2x is

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Image of the point (–1, 3) with respect to the line $y = 2 x$ is