The inequality $$12x6$$−$$2x4$$<$$2x2$$ is valid for x belongs to

$$22x4-x6$$ $$0$$ ⇒$$x2(x$$−$$1)2(x+1)2$$>$$0$$ which is true always except at $$x=0$$,$$1$$,−$$1$$

The inequality $$12x6$$−$$2x4$$<$$2x2$$ is valid for x belongs to

Correct option is 4(−∞,−1)∪(−1,0)∪(0,1)∪(1,∞)

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$The inequality {(\frac{1}{2})}^{x^{6} - 2 x^{4}} < 2^{x^{2}} is valid for x belongs to$

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(0,∞)

(−∞,−1)∪(−1,∞)

(−∞,−1)∪(−1,0)∪(0,1)∪(1,∞)

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detailed solution

Correct option is D

22x4-x6 <2x2⇒2x4-x60⇒x2x4-2x2+1>0 ⇒x2(x−1)2(x+1)2>0 which is true always except at x=0,1,−1

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The inequality 12x6−2x4<2x2 is valid for x belongs to

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$The inequality {(\frac{1}{2})}^{x^{6} - 2 x^{4}} < 2^{x^{2}} is valid for x belongs to$