The inflection points on the graph of function y=∫0x (t−1)(t−2)2dt are
x=–1
x=3/2
x=4/3
x=1
dydx=(x−1)(x−2)2 so d2ydx2=(x−2)(3x−4).
The points of inflection are given by d2ydx2=0 so x=2, x=4/3
are points of inflection.