First slide
Evaluation of definite integrals
Question

The inflection points on the graph of function y=0x(t1)(t2)2dt are

Moderate
Solution

dydx=(x1)(x2)2 so d2ydx2=(x2)(3x4).

The points of inflection are given by d2ydx2=0 so x=2, x=4/3 

are points of inflection.

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