Q.

The integer 'k' , for which the inequality x2−23k−1x+8k2−7>0  is valid for every x in R , is

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a

0

b

2

c

3

d

4

answer is C.

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Detailed Solution

x2−23k−1x+8k2−7>0,∀x∈R⇒   D<023k−12−4.8k2−7<0 49k2−6k+1−32k2+28<0k2−6k+8<0  k−4k−2<0 2
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