Q.
The integer 'k' , for which the inequality x2−23k−1x+8k2−7>0 is valid for every x in R , is
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a
0
b
2
c
3
d
4
answer is C.
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Detailed Solution
x2−23k−1x+8k2−7>0,∀x∈R⇒ D<023k−12−4.8k2−7<0 49k2−6k+1−32k2+28<0k2−6k+8<0 k−4k−2<0 2
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