An integer m is said to be related to another integer n if m is a multiple of n. Then the relation is

For any integer n, we have n|n⇒nRnSo, nRn for all n∈Z⇒R is reflexiveNow 2|6 but 6+2⇒(2, 6)∈R but 6, 2∉RSo, R is not symmetric.Let (m, n)∈R and (n, p)∈R.Then (m, n)∈R⇒m|n                                ⇒m|p⇒(m, p)∈R (n, p)∈R⇒n|pSo, R is transitive.Hence, R is reflexive and transitive but it is not symmetric.