The integer n for which Ltx→0cosx−1cosx−exxn is a finite nonzero number is
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a
1
b
2
c
3
d
4
answer is C.
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Detailed Solution
cosx−1cosx−ex=1−x22!+x44!−⋅⋅⋅−11−x22!+x44!−⋅⋅⋅−1+x+x22!+x33!⋅⋅⋅=x2−12+x24!⋅⋅⋅−x−x2−x33!⋅⋅⋅=x3−12+x24!⋅⋅⋅−1−x−x23!⋅⋅⋅(cosx−1)cosx−exx3=12+ terms containing x and higher powers of xLtx→0cosx−1cosx−exx3=12 ⇒n=3.