The integral ∫$$dx(x+4)87(x-3)67$$ is equal to: (where$$ C is a constant of $$integration)

Correct option is 2x−3x+41/7+C

Questions

$The integral \int \frac{d x}{(x + 4)^{\frac{8}{7}} (x - 3)^{\frac{6}{7}}} is equal to: (where C is a constant of integration)$

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−113x−3x+4−13/7+C

x−3x+41/7+C

−x−3x+41/7+C

12x−3x+43/7+C

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detailed solution

Correct option is B

Let I=∫x-3x+4-671(x+4)2dx Put x-3x+4=t7⇒7(x+4)2dx=7t6dt So, I=∫t-6t6dt=t+c=x-3x+417+c

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The integral ∫dx(x+4)87(x-3)67 is equal to: (where C is a constant of integration)

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$The integral \int \frac{d x}{(x + 4)^{\frac{8}{7}} (x - 3)^{\frac{6}{7}}} is equal to: (where C is a constant of integration)$