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Q.

The integral ∫dx(x+4)87(x-3)67 is equal to: (where C is a constant of integration)

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a

−113x−3x+4−13/7+C

b

x−3x+41/7+C

c

−x−3x+41/7+C

d

12x−3x+43/7+C

answer is B.

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Detailed Solution

Let I=∫x-3x+4-671(x+4)2dx Put x-3x+4=t7⇒7(x+4)2dx=7t6dt So, I=∫t-6t6dt=t+c=x-3x+417+c

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