The integral of f(x)=3xcosx is given by
3x(sinx+cosxlog3)+C
3x(log3sinx+cosx)+C
3x(sinx+coslog3)1+(log3)2
3x(log3sinx+cosx)1+(log3)2+C
I=∫3xcosxdx =3xsinx−log3∫3xsinxdx =3xsinx−log3−3xcosx+(log3)∫3x cos x dx]
=3xsinx+(log3),3xcosx−(log3)2⇒ 1+(log3)2I=3x(sinx+(log3)cosx)I=3x(sinx+(log3)cosx)1+(log3)2