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The integral $I = \int_{0}^{2} [x^{2}] d x ([t]$ denotes the greatest
integer less than or equal to t) is equal to:

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5−23

5−2−3

6−2−3

3−2

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detailed solution

Correct option is B

∫02 x2dx=∫01 x2dx+∫12 x2dx+∫23 x2dx+∫32 x2dx=∫01 0dx+∫12 1dx+∫23 2dx+∫32 3dx=0+(2−1)+2(3−2)+3(2−3)=−2−3+5

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The integral I=∫02 x2dx ([t] denotes the greatestinteger less than or equal to t) is equal to:

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The integral $I = \int_{0}^{2} [x^{2}] d x ([t]$ denotes the greatest
integer less than or equal to t) is equal to: