Integral value of x which satisfies the equation log654+logx16=log2x−log36(4/9) is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 4.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
log654+logx16=log2x−log3649 or 1+2log63+logx16=2log2x−log623 or 1+2log63+logx16=2log2x−log62+log63 or 1+logx16=2log2x−log62+log63 or 1+logx16=2log2x−1 or 4log2x=2log2x−2⇒ t=2 or t=−1⇒ x=4 or 1/2