Integration of f(x)=1+x2 with respect to x2, is
231+x23/2x+C
231+x23/2+C
2x31+x23/2+C
none of these
Let
I=∫f(x)dx2=∫1+x2dx2⇒ I=∫1+x2d1+x2 ∵dx2=d1+x2⇒ I=231+x23/2+C