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Q.

The inverse of the function y=10x−10−x10x+10−x is

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a

log10(2−x)

b

12log101+x1−x

c

12log10(2x−1)

d

14log2x2−x

answer is B.

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Detailed Solution

y(10x+10−x)=10x−10−x⇒102x(y−1)=−1−y ⇒x=12log101+y1−y. Thus f−1(x)=12log101+x1−x.

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