The inverse of the matrix $$A=Sec$$⁡θ−Tan⁡θ−Tan⁡θSec⁡θ is

Correct option is 3SecθTanθTanθSecθ

Questions

$The inverse of the matrix A = [\begin{array}{cc} Sec θ & - Tan θ \\ - Tan θ & Sec θ \end{array}] is$

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1−sinθ−sinθ1

cosθ−sinθ−sinθcosθ

SecθTanθTanθSecθ

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detailed solution

Correct option is C

The inverse of A=a bc d is 1ad−bcd−b−ca⇒A−1=1Se2θ−Tan2⁡θSec⁡θ−Tan⁡θ−Tan⁡θsec⁡θ⇒A−1=Sec⁡θTan⁡θTan⁡θSec⁡θ

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The inverse of the matrix A=Sec⁡θ−Tan⁡θ−Tan⁡θSec⁡θ is

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$The inverse of the matrix A = [\begin{array}{cc} Sec θ & - Tan θ \\ - Tan θ & Sec θ \end{array}] is$