The inverse of the proposition (p∧~q)→r is
~r→(~p∨q)
r→p∧~q)
(~p∨q)→∼r
None of these
Inverse of p→q is ~p→∼q
Therefore, inverse of (p∧~q)→r is
~(p∧~q)→∼r ≡∼(p∨q)→∼r