The inverse of the proposition (p∧~q)→r is
r⇒p∧~q
~p⇒p∨q
~p∨q⇒~r
None of these
Inverse of p⇒q is ~p⇒∼q
Inverse of (p∧~q)⇒r is ~p∧~q⇒∼r . Thus, (~p∨q)⇒∼r
Hence, (c) is true.