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$It is given that the events A and B are such that P (A) = \frac{1}{4}, P (\frac{A}{B}) = \frac{1}{2}, P (\frac{B}{A}) = \frac{2}{3} then P (B) =$

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Correct option is B

PBA=P(A∩B)P(A)⇒ 23=P(A∩B)1/4⇒ P(A∩B)=14⋅23=16PAB=P(A∩B)P(B)⇒12=1/6P(B)⇒ P(B)=1/61/2=26=13

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It is given that the events A and B are such that P(A)=14, PAB=12,PBA=23 then P(B)=

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$It is given that the events A and B are such that P (A) = \frac{1}{4}, P (\frac{A}{B}) = \frac{1}{2}, P (\frac{B}{A}) = \frac{2}{3} then P (B) =$