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Q.

Kunal Gaba has n objects, each of weight w. He weighs them in pairs and finds the sum of the weights of all possible pairs is 120g. When his friend Rakshit weighs them in triplets, the sum of all possible weights is 240g. The value of n is

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a

7

b

6

c

5

d

10

answer is B.

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Detailed Solution

According to the given conditionand           nC2(2w)=120 ⇒ n(n−1)w=120 nC3(3w)=240 ⇒ n(n−1)(n−2)w=480Thus,      n(n−1)(n−2)wn(n−1)w=480120⇒ n−2=4 ⇒ n=6
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