Questions
Kunal Gaba has objects, each of weight . He weighs them in pairs and finds the sum of the weights of all possible pairs is 120g. When his friend Rakshit weighs them in triplets, the sum of all possible weights is 240g. The value of is
detailed solution
Correct option is B
According to the given conditionand nC2(2w)=120 ⇒ n(n−1)w=120 nC3(3w)=240 ⇒ n(n−1)(n−2)w=480Thus, n(n−1)(n−2)wn(n−1)w=480120⇒ n−2=4 ⇒ n=6Similar Questions
is equal to
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