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$L e t n b e a p o s i t i v e i n t e g e r s u c h t h a t \sin \frac{π}{2 n} + \cos \frac{π}{2 n} = \frac{\sqrt{n}}{2}, t h e n n =$

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n=6

n=123..8

n=5

n=4

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detailed solution

Correct option is A

We have sinπ2n+cosπ2n=n2 Since -2≤sinπ2n+cosπ2n≤2 ⇒-2≤n2≤2 ⇒-22≤n≤22 ⇒0≤n≤8 We can see that n=6 satisfies the given equation

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Let n be a positive integer such that sinπ2n+cosπ2n=n2, then n=

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$L e t n b e a p o s i t i v e i n t e g e r s u c h t h a t \sin \frac{π}{2 n} + \cos \frac{π}{2 n} = \frac{\sqrt{n}}{2}, t h e n n =$