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$\underset{n \to \infty}{L i m} \frac{1}{n^{3}} {1 + 3 + 6 + ............ + \frac{n (n + 1)}{2}} =$

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Correct option is C

Given limit is ∑r=1n r2 +r2 n3

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Limn→∞1n3{1+3+6+............+n(n+1)2}=

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$\underset{n \to \infty}{L i m} \frac{1}{n^{3}} {1 + 3 + 6 + ............ + \frac{n (n + 1)}{2}} =$