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Limn→∞1+12+14+....+12n1+13+19+....+13n=

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a

4/3

b

34

c

0

d

12

answer is A.

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Detailed Solution

limn→∞1+12+14+....+12n1+13+19+.....+13n=limn→∞11-12n1-121-13n1-13 sum of n terms in GP =a1-rn1-r =43limn→∞1−12n1−13n=431-01-0=43 since rn→0 as n→∞ if r<1=43

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