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Q.

Ltn→∞1.1!+2.2!+3.3!+......n.n!n+1!=

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a

0

b

∞

c

1

d

-1

answer is C.

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Detailed Solution

Ltn→∞1⋅1!+2⋅2!+⋅⋅⋅+n⋅n!n+1!=Ltn→∞2!−1!+3!−2!+4!−3!+⋅⋅⟩⋅+n+1!−n!n+1!Ltn→∞n+1!−1!n+1!=Ltn→∞1−1n+1!=1−0=1.

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