Q.
The largest integer n such that 33! is divisible by 2n is
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a
30
b
31
c
32
d
None of these
answer is B.
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Detailed Solution
In terms of prime factors 33! can be written as 2a ⋅ 3b 5c ⋅ 7d …Now, E2 (33!)=332+3322+3323+3324+3325=16+8+4+2+1=31.Hence, the exponent of 2 in 33! is 31.∴ Largest value of n is 31.
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