First slide
Permutations
Question

The largest integer n such that 33! is divisible by 2n is

Moderate
Solution

In terms of prime factors 33! can be written as 2a ⋅ 3b 5c ⋅ 7d …

Now, E2 (33!)

=332+3322+3323+3324+3325=16+8+4+2+1=31.

Hence, the exponent of 2 in 33! is 31.

∴ Largest value of n is 31.

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App