The largest interval in which the function f(x)=3sin(π216−x2) assumes values is :
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a
[0,32]
b
[−32,32]
c
[-3 , 3]
d
None of these
answer is A.
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Detailed Solution
f is defined only if π216−x2≥0 i.e. x2≤π216⇒x≤π4 or x≥−π4 ⇒−π4≤x≤π/4 .Since f(−π/4)=0,f(π/4)=0 and f(0)=3sinπ4=32 .∴ f takes values in the interval [0,32] .