The largest interval for which x12−x9+x4−x+1>0 is
−4<x≤0
0<x<1
−100<x<100
−∞<x<∞
Given expression x12−x9+x4−x+1=f(x)
for x<0 put x=−y where y>0
then we get
f(−y)=y12+y9+y4+y+1>0 for y>0
For 0<x<1,x9<x4⇒−x9+x4>0 Also 1−x>0 and x12>0
⇒ x12−x9+x4+1−x>0⇒f(x)>0 For x>1,f(x)=xx3−1x8+1+1>0 Also x=0 and x=1 satisfy the inequality. So f(x)>0 for −∞<x<∞