Questions
The largest term common to the sequences 1, 11, 21, 31…….. to 100 terms and 31, 36, 41, 46……. to 100 terms is
a
381
b
471
c
281
d
521
detailed solution
Correct option is D
100th term 1, 11, 21, 31, ….. is 1+ (100 -1) 10 = 991.100th term of 31, 36, 41, 46…. Is 31+ (100-1) 5 = 526.Let the largest common term be 526. Then,526 = 31+(n-1) 10 ⇒n=50.5But n is an integer, hence n=50. Hence , the largest common term is 31+50−110=521Talk to our academic expert!
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