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The largest term common to the sequences 1,11,21,31,… to 100 terms and 31,36,41,46,… to 100 terms is

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b
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c
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d
521

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detailed solution

Correct option is D

tm=tn1+(m−1)10=31+(n−1)5⇒m=n+72=λ⇒m=λ,n=2λ−7⇒m≤100,n≤1002λ−7=1002λ≤107λ=53  number of common terms are 53 the largest common term is t53=1+52×10=521


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