Q.
The largest term common to the sequences 1,11,21,31,… to 100 terms and 31,36,41,46,… to 100 terms is
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a
381
b
471
c
281
d
521
answer is D.
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Detailed Solution
tm=tn1+(m−1)10=31+(n−1)5⇒m=n+72=λ⇒m=λ,n=2λ−7⇒m≤100,n≤1002λ−7=1002λ≤107λ=53 number of common terms are 53 the largest common term is t53=1+52×10=521
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