The largest term in the expansion of (3+2x)50 where x=15 is

∵(3+2x)50=3501+2x350 Here, Tr+1=35050Cr2x3r and  Tr=35050Cr−12x3r−1but x=15     ( given)∴ Tr+1Tr≥1⇒ 50Cr 50Cr−123⋅15≥1⇒ 102−2r≥15r⇒r≤6