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$The largest terms of the sequence \frac{1}{503}, \frac{4}{524}, \frac{9}{581}, \frac{16}{692}, \dots is$

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16692

4524

491529

641529

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detailed solution

Correct option is C

Tn=n2500+3n3=f(n)f1(n)=n1000−3n3500+3n32 For the maxima or minf1(n)=0n=100031/3 Now 6<100031/3<7∴T7 is the largest term. the largest term of the sequence =49500+1029=491529

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The largest terms of the sequence 1503,4524,9581,16692,… is

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$The largest terms of the sequence \frac{1}{503}, \frac{4}{524}, \frac{9}{581}, \frac{16}{692}, \dots is$