The largest value of the non-negative integer a for which limα→1 −ax+sin(x−1)+ax+sin(x−1)−11−x1−x=14, is
2
3
4
5
We have.
limα→1 −ax+sin(x−1)+ax+sin(x−1)−11-x1-x=14
⇒limα→1 sin(x−1)x−1−a1+sin(x−1)x−11+x=14
⇒ 1−a22=14⇒ a2−2a=0⇒a=0,2