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The largest value of the positive integer k for which nk+1 divides  1+n+n2++n127 is divisible by

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a
8
b
16
c
32
d
64

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detailed solution

Correct option is D

We have,1+n+n2+…+n127=n128−1n−1=n64−1n64+1n−1=1+n+n2+…+n63n64+1∴ k = 64 which is divisible by 8, 16, 32 and 64.


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