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The last digit of (1! + 2! + ....... + 2009!)500 is 

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a
1
b
2
c
7
d
9

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detailed solution

Correct option is A

As 1!+2!+3!+4!=33 and last digit of n!, forn≥5is 0, last digit of (1!+2!+⋯+2009!)500 is same as that of last digit of  3500 But 3500 =9250=(10-1)250 and last digit of (10-1)250 is 1.


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