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The last digit of $3^{3^{4 n}} + 1, n \in N$ is

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Correct option is D

∵34n=81n=(1+80)n=1+80λ,λ∈N∴334n=31+80λ=3⋅380λ=3⋅(9)40λ=3(10−1)40λ=3(1+10μ)=3+30 μ∴ Lastdigitof 334n+1 is 4.

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The last digit of 334n+1,n∈N is

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The last digit of $3^{3^{4 n}} + 1, n \in N$ is