The last digit of 334n+1,n∈N is
4C3
8C7
8
4
∵34n=81n=(1+80)n=1+80λ,λ∈N
∴334n=31+80λ=3⋅380λ=3⋅(9)40λ=3(10−1)40λ
=3(1+10μ)=3+30 μ
∴ Lastdigitof 334n+1 is 4.