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Q.

The least difference between the roots of the equation 4cosx(2−3sin2x)+(cos2x+1)=0(0≤x≤π2)

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a

π6

b

π4

c

π3

d

π2

answer is A.

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Detailed Solution

4cosx2-3+3cos2x+2cos2x=02cosx(3cosx+2)(2cosx−1)=0 ⇒cosx=0 (or) cosx=12⇒x=π2 (or) x=π3∴ required difference =π6

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