The least difference between the roots, in the first quadrant 0≤x≤π2 of the equation 4cosx2−3sin2x+cos2x+1=0, is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

π6

π4

π3

π2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

We have 4cosx3cos2x−1+2cos2x=0⇒2cosx3cosx+22cosx−1=0⇒cosx=0 or cosx=12 ∵cosx≠-23 as 0≤x≤π2 ⇒x=π2 or π3 ∴the difference of values is π2-π3=π6

Watch 3-min video & get full concept clarity