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The least difference between the roots, in the first quadrant $(0 \leq x \leq \frac{π}{2})$ of the equation $4 \cos x (2 - 3 \sin^{2} x) + (\cos 2 x + 1) = 0$ , is

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Correct option is A

We have 4cosx3cos2x−1+2cos2x=0⇒2cosx3cosx+22cosx−1=0⇒cosx=0 or cosx=12 ∵cosx≠-23 as 0≤x≤π2 ⇒x=π2 or π3 ∴the difference of values is π2-π3=π6

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The least difference between the roots, in the first quadrant 0≤x≤π2 of the equation 4cosx2−3sin2x+cos2x+1=0, is

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The least difference between the roots, in the first quadrant $(0 \leq x \leq \frac{π}{2})$ of the equation $4 \cos x (2 - 3 \sin^{2} x) + (\cos 2 x + 1) = 0$ , is