The least difference between the roots, in the first quadrant 0≤x≤π2 of the equation 4cosx2−3sin2x+cos2x+1=0, is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

π6

π4

π3

π2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We have 4cosx3cos2x−1+2cos2x=0⇒2cosx3cosx+22cosx−1=0⇒cosx=0 or cosx=12 ∵cosx≠-23 as 0≤x≤π2 ⇒x=π2 or π3 ∴the difference of values is π2-π3=π6

Watch 3-min video & get full concept clarity