The least integral value of x satisfying the equation ∣x2−1+log⁡x|=|x2−1|+|log⁡x∣ is

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answer is 1.

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Detailed Solution

x2−1+log⁡x=x2−1+|log⁡x|⇒x2−1log⁡x≥0 We must have x>0⇒x∈(0,∞)⇒ Least integral value of x is 1