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The least positive integral value of x for which $^{10} C_{x - 1}$ $> 2 (^{10} C_{x})$

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Correct option is B

10Cx−1>2 10Cx⇒10!(x−1)!(11−x)!>210!x!(10−x)!⇒x>2(11−x)⇒3x>22⇒x>7⇒x≥8.Thus, least positive integral value of x is 8

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The least positive integral value of x for which 10Cx−1>2 10Cx

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The least positive integral value of x for which $^{10} C_{x - 1}$ $> 2 (^{10} C_{x})$