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Introduction to linear inequalities

Question

The least positive integral value of x for which 1x2+1x1>1x is true is 

Moderate
Solution

1x2+1x1>1x 2x23xx2+3x2(x2)(x1)x>0 x22(x2)(x1)x>0

 

x(2,0)(1,2)(2,)



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The solution of x1=(x[x])(x{x})  (where [x]  and {x}  are the integral and fractional part of x ) is :


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