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The least positive root of the function $\sin x - π / 2 + 1 = 0$ lies in the interval

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[0,π/2]

[π/2,π]

[π/2,3π/2]

none of these

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detailed solution

Correct option is A

sin⁡x=π2−1=2214−1=814=47 so the least positive root lies in [0,π/2]

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The least positive root of the function sin⁡x−π/2+1=0 lies in the interval

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The least positive root of the function $\sin x - π / 2 + 1 = 0$ lies in the interval