The length of a longest interval in which the function 3sinx−4sin3x is incresing is
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a
π/3
b
π/2
c
3π/2
d
π
answer is A.
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Detailed Solution
Since 3sinx−4sin3x=sin3x and sin3x increases when 3x takes values from −π/2 to π/2 or x takes values from −π/6 to π/6. Thus, the length of the longest interval in which 3sinx−4sin3x increases is π/6−(−π/6)=π/3.