Q.

The length of the perpendicular from the origin, on the normal to the curve, x2+2xy-3y2=0 at the point (2,2) is:

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a

42

b

22

c

2

d

2

answer is B.

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Detailed Solution

x2+2xy−3y2=0⇒dydx=−x+yx−3y⇒dydx2,2=1 Equation of normal is x + y = 4Perpendicular distance from origin0+0−42=22
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