The length of the perpendicular from the origin to the plane passing through the point a→ and containing the line r→=b→+λc→ is
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a
[a→b→c→]|a→×b→+b→×c→+c→×a→|
b
[a→b→c→]|a→×b→+b→×c→|
c
[a→b→c→]∣b→×c→+c→×a→∣
d
[a→b→c→]|c→×a→+a→×b→|
answer is C.
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Detailed Solution
The given plane passes through a→ and is parallel to the vectors b→−a→ and c→ So it is normal to (b→−a→)×c→ Hence, its equation is (r→−a→)⋅((b→−a→)×c→)=0or r→⋅(b→×c→+c→×a→)=[a→b→c→]The length of the perpendicular from the origin to this plane is [a→b→c→]|b→×c→+c→×a→|