The length of the tangent drawn from any pointon the circle x2+y2+2gx+2fy+c=0 to the circlex2+y2+2gx+2fy+c1=0 is
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a
c1⋯c
b
c−c1
c
c−c1
d
c1−c
answer is D.
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Detailed Solution
Let (α,β) be a point on x2+y2+2gx+2fy+c=0 Then, the length of the tangent from (α,β) tox2+y2+2gx+2fy+c1=0 is given by l=α2+β2+2gα+2fβ+c1Since (α,β) lies on x2+y2+2gx+2fy+c=0 ∴ α2+β2+2gα+2fβ=−cHence l=c1−c