The length of the tangent drawn from any pointon the circle x2+y2+2gx+2fy+c=0 to the circlex2+y2+2gx+2fy+c1=0 is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
c1⋯c
b
c−c1
c
c−c1
d
c1−c
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let (α,β) be a point on x2+y2+2gx+2fy+c=0 Then, the length of the tangent from (α,β) tox2+y2+2gx+2fy+c1=0 is given by l=α2+β2+2gα+2fβ+c1Since (α,β) lies on x2+y2+2gx+2fy+c=0 ∴ α2+β2+2gα+2fβ=−cHence l=c1−c