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The length of the tangent from (0, 0) to the circle
$2 (x^{2} + y^{2}) + x - y + 5 = 0$ is

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Correct option is D

The equation of the circle can be written as x2+y2+12x−12y+52=0Let I be the length of tangent drawn from (0, 0) to the given circle. Then, l=S1=0+0+0−0+52=52

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The length of the tangent from (0, 0) to the circle 2x2+y2+x−y+5=0 is

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The length of the tangent from (0, 0) to the circle
$2 (x^{2} + y^{2}) + x - y + 5 = 0$ is