Let A=aâ â â â bcâ â â â d be such that A3=O but Aâ O, then
A2=O
A2 = A
A2 = I â A
none of these
As A3=O, we get A3=0
|A|3=0â|A|âadâbc=0
Also,
A2=a2+bc(a+d)b(a+d)cbc+d2=a2+ad(a+d)b(a+d)cad+d2=(a+d)A
If a+d=0 we get A2=O.
Suppose a+dâ 0, then
A3=A2A=(a+d)A2â O=(a+d)A2âA2=O