First slide
Operations of matrix
Question

Let A=a    bc    d be such that A3=O but A≠O, then

Moderate
Solution

As A3=O, we get A3=0

|A|3=0⇒|A|⇒ad−bc=0

Also, 

A2=a2+bc(a+d)b(a+d)cbc+d2=a2+ad(a+d)b(a+d)cad+d2=(a+d)A

If a+d=0 we get A2=O.

Suppose a+d≠0, then

 A3=A2A=(a+d)A2⇒  O=(a+d)A2⇒A2=O

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